find the area of the shaded portion
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Given:-
- DC = 11 cm
- BC = 14 cm
- EG = 5 cm
- HF = 4 cm
- ∠GEB = ∠HFC = 90°
To find:-
- Area of the shaded region.
Answer:-
For □ABCD:
Area of rectangle ABCD = BC * DC
= 14 cm * 11 cm
= 154 cm²
For △AGB:
As GE is the altitude/height, we can say that,
Area of △AGB = (1/2) * AB * GE
And as ABCD is a rectangle, AB = DC = 11 cm
So, area of △AGB = (1/2) * (11 cm) * (5 cm)
= 55/2 cm²
= 27.5 cm²
For △DHC:
As HF is altitude/height, we can say that,
Area of △DHC = (1/2) * DC * HF
= (1/2) * (11 cm) * (4 cm)
= 44/2 cm²
= 22 cm²
We observe that,
area of shaded region = Area of □ABCD - (Area of △AGB + Area of △DHC)
= 154 cm² - (27.5 cm² + 22 cm²)
= 154 cm² - 49.5 cm²
= 104.5 cm² Ans.
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