Question

Find the area of the shaded portion. ​

Answer 1

Answer:

166.86cm²

Step-by-step explanation:

Area of trapezium - 2(Area of semicircles) or Area of circle

$\frac{a + b}{2}h$ - πr²

$\frac{28 + 12}{2}14 + \frac{22}{7}6^{2}$

40/2 x 14

= 40 x 7

= 280

22/7 x 36

792/7

= 113.14

Now add:-

280 - 113.14

= 166.86cm²

Answer 2

The area of the shaded portion is 181.73 cm.

Step-by-step:

The white part looks like 2 semicircles.

The total diameter of both semicircles= 12cm

The diameter of one semicircle= $\frac{12}{2}$cm=6cm

The diameter of one semicircle= $\frac{6}{2}$cm=3cm

We know that 2 semicircles make 1 circle

So the area of the two semicircles is the area of one circle

Area=πr2=π×3^2≈28.27433

In the trapezium bottom base is 12cm,

top base is 28cm, and

height is 48cm.

Area=$\frac{a+b}{2}$h=$\frac{12+18}{2}$×14=210

Area of shaded part= area of trapezium excluding the area of the semicircles=210-28.27433=181.72567