find the area of the shaded portion in each of the following figures
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0
Answer:
8.4+0.49π(m^2)
Step-by-step explanation:
Merge the two semicircles, you get a circle or r=0.7m
πr^2 where r=0.7, you get 0.49π
1.4+0.5x2=2.4
3.5x2.4=8.4
8.4+0.49π is the answer, just add square metres and you got it
Answered by
1
Answer:
Area of rectangle = 28 m × 26 m
= 728 m2
(i) Perimeter of the shaded position
= 2 × 28 + 2 × 26 – 4 × 20 + 2 × 22/7 × 10
= 56 + 52 – 80 + 440/7
= 108 – 80 + 62.85
= 170.85 – 80 = 90.85 m
(ii) Area of one corner (unshaded) = 1/4π × (10)2
= ¼ × (3.14)(100 m2)
= 314/4
= 78.5 m2
∴ Area of 4 corner (unshaded) = 78.5 × 4 = 314 m2
∴ Area of the shaded portion = [728 – 314] m2
= 414 m2
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