Question

find the area of the shaded portion in the ​

Answer 1

GIVEN :-

• Length of Rectangle = 40 cm.
• Breadth of Rectangle = 20 cm.
• Altitude of Triangle = 10 cm.
• Base of triangle = 20 cm.

TO FIND :-

• The area of shaded Portion.

SOLUTION :-

⇒ Area of shaded Portion = Area of rectangle - 2 × Area of Triangle.

⇒ Area of shaded Portion = Length × Breadth - 2 × 1/2 × base × Height.

⇒ Area of shaded Portion = 40 cm × 20 cm - 20 cm × 10 cm

⇒ Area of shaded Portion = 800 cm ² - 200 cm²

⇒ Area of shaded Portion = 600 cm²

Hence the area of the shaded Portion is 600 cm².

Answer 2

Answer:

$\huge \bf \: given$

Length of triangle (L) = 40 cm

Breadth of triangle (B) = 20 cm

Altitude of triangle (A) = 10 cm

Base of triangle (b) = 20 cm

$\huge \bf \: shaded \: portion$

Concept - There is a rectangle area in which some parts are shaded and other not. We have to find the shaded region of triangle.

First we have to find area of rectangle

$\sf\huge \: area \small (rectangle) = \huge \: l \times b$

$\sf \: area \: = 40 \times 20$

$\sf \: area \: of \: rectangle \: = 800 \: cm$

Now,

$\sf \: area \: of \: shaded \: portion = area of rectangle - area of triangle$

$\sf \: 800 - 2 \times \dfrac{1}{2} \times 20 \times 10$

$\sf \: 800 - 20 \times 10$

$\bf \: shaded \: region \: = 800 - 200 \: cm$

$\huge \sf Shaded\: area = 600 cm²$