Find the area of the shaded portion in the figure
28 cm 28 cm
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Fig. 22.42
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Answer:
(i) -2/3 x 3/5 + 5/2 - 3/5 x 1/6
= -2/3 x 3/5 - 3/5 x 1/6 + 5/2 [by commutativity]
= (-2/3 x 3/5) - (3/5 x 1/6) + 5/2
= 3/5 [-2/3 - 1/6] + 5/2 [by distributivity]
= -3/5 [2/3 + 1/6] + 5/2
= -3/5 [(4 + 1)/6] + 5/2
= -3/5 x 5/6 + 5/2
= -3/6 + 5/2
= -1/2 + 5/2
= (-1 + 5)/2
= 4/2
= 2
(ii) 2/5 x (-3/7) - 1/6 x 3/2 + 1/14 x 2/5
= 2/5 x (-3/7) + 1/14 x 2/5 - 1/6 x 3/2 [by commutativity]
= [2/5 x (-3/7)] + [1/14 x 2/5] - 1/6 x 3/2
= 2/5 [-3/7 + 1/14] - 3/12 [by distributivity]
= 2/5 [(-6 + 1)/14] - 1/4
= 2/5 x (-5/14) - 1/4
= -2/14 - 1/4
= (-4 - 7)/28
= -11/28
Step-by-step explanation:
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