Question

find the area of the shaded region
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Answer 1

Answer:

refer to the attachment

Answer 2

Answer:

cd=24 then

dq=12

dp²=pq²+dq²

=(12)²+(5)²

=144+25

=169

dp=13

ar(dpq)=1/2×12×5

=30

dpq=cpq

cpd=dpq+cpq

=30+30

=60

ar(abcd)=(ab+cd)×rb/2

=(24+18)×10/2

=42×5

=210

ar(abcd)+ar(dpc)=210+30=240