Find the area of the shaded region
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Answered by
0
Answer:
ANSWER
SO
2
(g)+1/2O
2
(g)⇌SO
3
(g) K
1
=4×10
−3
atm
−0.5
.
2SO
3
(g)⇌2SO
2
(g)+O
2
(g)
To get the equilibrium constant of the required equation:
K
1
=
[SO
2
][O
2
]
1/2
[SO
3
]
K
2
=
[SO
3
]
[SO
2
]
2
[O
2
]
K
2
=(
K
1
1
)
2
=
(4×10
−3
)
2
1
=6.25×10
4
Answered by
1
Answer:
80*60=4800m² the whole area
70*50=3500m² the area of middle part
so the area of shaded part is (4800-3500)=300m²
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