Find the area of the shaded region.
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Area of middle part
area of rectangle + 2* area of hemisphere
In rectangle
B=12-4-4=12-8=4cm
L=26-3-3=26-9=17cm
Area= 17*4+2*pi*r^2/2
68+2*22/7*2*2/2
68+88/7
68+12.57
80.57cm^2
Now area of big rectangle = L*B
12*26=312cm^2
area of shaded region = 312-80.57=231.43cm^2
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Answer: 6.57m^2
Step-by-step explanation:
length of the unshaded region =26-(3+3)=20m
Radius of the unshaded region =12-(4+4) =4m=2m. Taking Pi=22/7
Therefore its Area=(2 π r h+2 π r^2) +(2 π r^2)
(2 x 22/7 x 2 x 16 + 2 x 22/7 x 2 x 2) + (2 x 22/7 x 2 x 2)
=1760/7m^2
Total area of the rectangle =(L X B)
Length=26m
Breadth=12m
26 x 12
=312m^2
Therefore the area of the shaded portion=312-1760/7
=424/7=60.57m^2
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