Question

find the area of the shaded region. Given APC and BPD are sin circles of radii 5cm​

Answer 1

Answer:

area of the shaded region =area of square-2(area of semicircle)X25/100

area of the shaded region$=(a^2-\frac{22}{7} r^2) (\frac{25}{100})$

Step-by-step explanation:

area of the shaded region =area of square-2(area of semicircle)X25/100

$=(a^2-\frac{22}{7} r^2) (\frac{25}{100})$