Math, asked by siddharthk7704, 1 year ago

Find the area of the shaded region given in the figure.

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Answers

Answered by HarishAS
24

Hey friend , Harish here.

Here is your answer.

This is really a interesting and tricky problem. So we have many hard solutions and a very simple solution for this problem.

Let's look for the simplest solution possible from our basics.

So for making it simple we need some we need to recall some basic concepts.

Recalling the basics :

1)  \mathrm{Area\ of\ \Delta} \mathrm{= \frac{1}{2}\times base\times height}

So for same base and height areas of two triangles are equal.

Now lets see how to make it use this concept. A little construction will help here.

Construction :

Connect the point inside the quadrilateral to all the vertex , making it a whole of 8 triangle. (REFER TO THE IMAGE ATTACHED)

Now, from the image we can notice that the every two triangles with same base and height as equal area. So let us mark the areas of 8 triangles as p,q,r,s.

Now we know that :

(p+q) + (r+s) = (q+r) + (s+p)

We know that :

(p + q) = 16 ; (r + s) = 32 ; (q + r) = 20

Also it is easy to notice that area that is unknown = (s+p)

So from this we can find that , Unknown area = (16 + 32) - 20

= 28

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Hope my answer is helpful to you.

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siddharthk7704: Thanks
druchand: 32 cm2 seems more logical...
The total area gotta be a perfect square of even number.
20+32+16=68. Next perfect square number is 10x10=100 or 12x12=144. If it's 144 the answer is 76 which seems very large. And if it's 100 the answer is 20+32+16+ X = 100 so X = 32.
HarishAS: @Druchand nice approach..
HarishAS: But not one thing..Sides of the square may not be integral.
HarishAS: So wrong assumption.
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