Find the area of the shaded region. Here ABC is a right-angled triangle where AB = 8 cm,
BC = 6 cm and ADC, BEC and AFB are semicircles.
Answers
Answer:
which is shaded here say
Given:
ABC is a right-angled triangle where AB = 8 cm, BC = 6 cm and ADC, BEC and AFB are semicircles.
To find:
The area of the shaded region
Solution:
Finding the area of the ΔABC:
We know,
- Area of a triangle = ½ × base × height
∴ Area of triangle ABC is,
= ½ × AB × BC
substituting the given values of AB & BC
= ½ × 8 × 6
= 4 × 6
= 24 cm²
Finding the area of semi-circle AFB:
We know,
- Area of a semi-circle = ½ ×
∴ Area of semi-circle AFB is,
= ½ ×
substituting the value of r =
= ½ × × 4²
=
= 25.14 cm²
Finding the area of semi-circle BEC:
∴ Area of semi-circle BEC is,
= ½ ×
substituting the value of r =
= ½ × × 3²
=
= 14.14 cm²
Finding the area of semi-circle ADC:
Using the Pythagoras theorem in Δ ABC, we get
AB² + BC² = AC²
⇒ 8² + 6² = AC²
⇒ 64 + 36 = AC²
⇒ 100 = AC²
⇒ AC = √100
⇒ AC = 10 cm
∴ Area of semi-circle ADC is,
= ½ ×
substituting the value of r =
= ½ × × 5²
=
= 39.28 cm²
Finding the area of the shaded region:
∴ The area of the shaded region is,
= [Area of triangle ABC] + [Area of semi-circle AFB] + [Area of semi-circle BEC] + [Area of semi-circle ADC]
= [24 cm²] + [25.14 cm²] + [14.14 cm²] + [39.28 cm²]
= 102.56 cm²
Thus,
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