Find the area of the shaded region if ABCD is a square
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shaded area = area of ΔABE + area of ΔCDE
= 16*4*1/2 + 16*12*1/2
= 16*16/2 = 128cm²
= 16*4*1/2 + 16*12*1/2
= 16*16/2 = 128cm²
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Length of side of the given square = 4+12 = 16cm .
Now Area of Unshaded triangles is composed of two right triangles .
Area of unshaded portion = 1/2(8)(16)+1/2(16)(8) = 64+64 = 128 cm²
Area of total figure = 16² = 256 cm² .
Hence,Area of shaded portion= Area of Square - Area of unshaded region = 256-128=128cm² .
Or Area of shaded portion = Area of ΔABE+ ΔEDC = 1/2(4)(16)+1/2(12)(16)=32+96=128cm²
Now Area of Unshaded triangles is composed of two right triangles .
Area of unshaded portion = 1/2(8)(16)+1/2(16)(8) = 64+64 = 128 cm²
Area of total figure = 16² = 256 cm² .
Hence,Area of shaded portion= Area of Square - Area of unshaded region = 256-128=128cm² .
Or Area of shaded portion = Area of ΔABE+ ΔEDC = 1/2(4)(16)+1/2(12)(16)=32+96=128cm²
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