find the area of the shaded region if PQ =24cm , o is the center of the circle
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Answer:
the area of the shaded region = 161.54 cm²
Step-by-step explanation:
PQ=24cm ,PR =7 cm
We know that any angle made by the diameter QR in the semicircle is 90°.
∴∠RPQ=90°
In right angled ∆RPQ
RQ
2
=PQ
2
+PR
2
[By pythagoras theorem]
RQ²=24²+7²
RQ²=576+49
RQ²=625
RQ=√625cm
RQ=25cm
now find radius and area of triangle by using formula.
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