Question

find the area of the shaded region if PQ=24cm,PR=7cm and O is the centre of the circle.​

Answer 1

Answer:

I help you.

Step-by-step explanation:

please make brilliant me

Answer 2

161.54 cm²

Step-by-step explanation:

PQ=24cm ,PR =7 cm

We know that any angle made by the diameter QR in the semicircle is 90°.

∴∠RPQ=90°

In right angled ∆RPQRQ 2 =PQ 2 +PR 2

[By pythagoras theorem]

RQ²=24²+7²

RQ²=576+49

RQ²=625

RQ=√625cm

RQ=25cm

radius of the circle (OQ)= RQ/2 = 22/5cm

Area of right ∆RPQ= 1/2 ×Base×height

Area of right ∆RPQ= 1/2×RP×PQ

Area of right ∆RPQ= 1/2×7×24=7×12=84cm²

Area of right ∆RPQ=84cm²

Area of semicircle= πr² / 2

= 22/7×25/2×25/2×1/2

= 11× 25×25/28

= 6875/28 cm²

Area of the shaded region = Area of semicircle - Area of right ∆ RPQ

= 6875/28 −84

= 6875 – 2352/28

= 4523/28 = 161.54 cm²