Math, asked by umadevidevikaa, 4 months ago

find the area of the shaded region in each of the following figure​

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Answers

Answered by Anonymous
1

Answer:

Step-by-step explanation:

Tʜᴇ ᴅɪᴀᴍᴇᴛᴇʀ ɪs 21 sᴏ ᴛʜᴇ ʀᴀᴅɪᴜs ᴡɪʟʟ ʙᴇ 21/2

10.5 ɪs ᴛʜᴇ ʀᴀᴅɪᴜs ᴏғ ᴄɪʀᴄʟᴇ

Sᴏ ᴀʀᴇᴀ ᴏғ ᴄɪʀᴄʟᴇ ɪs πʀ²

22/7 x 21/2 x 21/2 = 346.18

Sᴏ ᴀʀᴇᴀ ᴏғ ᴄɪʀᴄʟᴇ ɪs 346.18

Sᴏ ɪғ ᴡᴇ ᴀᴅᴅ ᴛᴡᴏ sᴇᴍɪᴄɪʀᴄʟᴇ ᴡᴇ ɢᴇᴛ ᴏɴᴇ ᴄɪʀᴄʟᴇ

Sᴏ 2 x 346.18 = 692.37

Sᴏ ᴀʀᴇᴀ ᴏғ ᴀʟʟ ᴛʜᴇ sʜᴀᴅᴇᴅ ʀᴇɢɪᴏɴ ᴡɪʟʟ ʙᴇ 693 ᴍ² ᴀᴘᴘʀᴏx.

Hᴏᴘᴇ ɪᴛ ʜᴇʟᴘs!!

Answered by ZAYNN
3

Answer:

Let the Diameter of each semi - circle be 21 cm as stated in the Question.

We can absorb that there are Four Semi - Circles which can form Two Circles of Diameter 21 cm.

\underline{\bigstar\:\textsf{According to the given Question :}}

:\implies\textsf{Area of Shaded Region = Area of 4 semi circles}\\\\\\:\implies\textsf{Area = Area of 2 circles}\\\\\\:\implies\sf Area = 2 \times Area \:of \:circle\\\\\\:\implies\sf Area = 2\pi \:r^2\\\\\\:\implies\sf Area=2 \times \dfrac{22}{7} \times \bigg(\dfrac{Diameter}{2}\bigg)^2\\\\\\:\implies\sf Area = 2 \times \dfrac{22}{7} \times \bigg(\dfrac{21}{2}\bigg)^2\\\\\\:\implies\sf Area = 2 \times \dfrac{22}{7} \times \dfrac{21}{2} \times \dfrac{21}{2}\\\\\\:\implies\sf Area = 11 \times 3 \times 21\\\\\\:\implies\sf Area=693\:cm^2

\therefore\:\underline{\textsf{Hence, area of the shaded region is \textbf{693 cm$\sf^2$}}}.

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