Question

Find the area of the shaded region in Fig. 12.19, if PQ = 24 cm, PR = 7 cm and O is the centre of the circle. R Р Fig. 12.19​

Answer 1

Answer:

898.14 cm2

Step-by-step explanation:

angle P is 90

bcz an angle subtends by a diameter in circle is always 90

so, by Pythagoras theorem

RQ^2 = PR^2+ PQ^2

RQ^2 = 24^2 + 7^2

RQ^2 = 576+ 49

RQ^2 = 625

RQ = 25

Area of shaded region = Area of semicircle - Area of triangle

area of semicircle = 1/2 ×22/7×25×25

= 6875/7 = 982.14cm^2

area of triangle = 1/2 × 24× 7 = 84cm^2

Area of shaded region = 982.14- 84 = 898.14 cm^ 2

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