Question

Find the area of the shaded region in fig. 2, where arcs drawn with centres a, b, c and d intersect in pairs at mid-points p, q, r and s of the sides ab, bc, cd and da respectively of a square abcd of side 12 cm. [use  = 3.14]

Answer 1

Answer:

30.96

Step-by-step explanation: Radius of each arc drawn = 6cm

Area of four quadrants = Area of circle = Pi r^2

3.14*6*6=113.04

Area of square = a^2

12*12=144

Area of shaded region = 144-113.04 =30.96

Answer 2

Area of the shaded region = Area of the square ABCD - 4 × Area of a quadrant or a circle with r = 6cm

$\longrightarrow$$\sf{12cm \times 12cm - \times \frac{1}{4} = 3.14 \times 6cm \times 6cm}$

$\longrightarrow$$\sf{(144 - 113.04) {cm}^{2} }$

$\longrightarrow$${\boxed{\sf{\red{{30.96cm}^{2}}}}}$