Find the area of the shaded region in figure shown, if
ABCD is a square of side 14 cm and APD and BPC are
semi-circles.
* চিত্রত দেখুওৱা আচ্ছাদিত অঞ্চলটোৰ কালি নির্ণয়
| কৰা, যদি 14 cm চেঃমিঃ বাহুৰ ABCD এটা
বর্গক্ষেত্ৰ আৰু APD আৰু BPC অর্ধবৃত্ত হয়।
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Answered by
1
Step-by-step explanation:
area of square= 14^2
= 196 cm^2
radius= 14/2
=7 cm
area of semicircle APD= area of semicircle BPC
(same radius)
area of APD=(πr^2)/2
=(22÷7)*7*7/2
=77cm^2
area of BPC=77cm^2
area of shaded region
=ar of square- area of both semicircles
=196-77-77
=42cm²
Answered by
1
98sq.cm
Step-by-step explanation:
Since the APD and BPC are 2equql triangles and their areas are 49+49=98sq.cm
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