Find the area of the shaded region in the adjoining figure, given that AB = 14 cm, AD = 12 cm, BD = 18 cm and angle DAB = angle CBA = 90°. [Hint: Draw DE perpendicular to BC]
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first of all as given in hint we will draw or De perpendicular to BC
that will create a triangle DEC, right angled at e
so we will find area of the triangle
=1/2 xbxh
=1/2x(18-12)x14
=1/2x6x14
=42cm square
now we will find the area of rectangle
=lxb
=14x12
=168 cm square
total area is equals to 168 plus 42 that is 210 CM square
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