Find the area of the shaded region in the figure, where a circular arc of radius 6 cm has been drawn with vertex O of an equilateral triangle OAB of side 12 cm as centre.!!
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Find the area of the shaded region in the figure, where a circular arc of radius 6 cm has been drawn with vertex O of an equilateral triangle OAB of side 12 cm as centre?
Here we can see that
Area of required figure = Area of circle+Area of triangle− Area of the sector
⇒A(circle)=πr²
⇒A(circle)=π6²
⇒A(circle)=36π
⇒A(triangle)= (√3/4)a²
⇒A(triangle)= (√3/4)×12²
⇒A(triangle)=36√3
⇒A(sector)= (1/2)r²θ
⇒A(sector)= 1/2(6²) π/3
⇒A(sector)=6π
Therefore, Required Area=36π+36√3. -6π
⇒ Required Area=30π+36√3
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Find the area of the shaded region in the figure, where a circular arc of radius 6 cm has been drawn with vertex O of an equilateral triangle OAB of side 12 cm as centre?
Ans : Here we can see that,
Area of required figure = Area of circle+Area of triangle− Area of the sector
⇒A(circle)=πr²
⇒A(circle)=π6²
⇒A(circle)=36π
⇒A(triangle)= (√3/4)a²
⇒A(triangle)= (√3/4)×12²
⇒A(triangle)=36√3
⇒A(sector)= (1/2)r²θ
⇒A(sector)= 1/2(6²) π/3
⇒A(sector)=6π
Therefore, Required Area=36π+36√3. -6π
⇒ Required Area=30π+36√3