Question

find the area of the shaded region in the figure where BD is the diameter. Take π = 3.14.​

Answer 1

Answer: 72.665 $cm^{2}$

Step-by-step explanation:

By pythagora's theorem,

BD=$\sqrt{5^{2}+12^{2} }$

BD=13cm

diameter of circle = 13cm

radius = 13/2cm

Area of circle = $\pi$$r^{2}$

area of circle = 3.14 * 13/2 *13/2

area of circle = 132.665cm2

area of Rectangle = 5*12=60cm2

Shaded area = 132.665-60 = 72.665cm2

Answer 2

In ΔABD;

AD² + AB² = BD²

5² + 12² = BD²

BD² = 169

BD = 13

BD = 2 × Radius

Radius = 13/2

Area of Circle = πr²

                      = (3.14 × 13 × 13) / 4

                      = 132.66 cm²

Area of Rectangle = 12 × 5

                             = 60 cm²

Area of Shaded Region = Area of Circle - Area of rectangle

                                       = 132.66 - 60

                                       = 72.66 cm²