Find the area of the shaded region in the following figure.
In the figure,ABCD is a square.
Please explain
Please answer it correctly
I will mark you as brainlist
Please answer it very fast
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![](https://hi-static.z-dn.net/files/d73/3457a99ce8b8c3a503b417f04e449d37.jpg)
Answers
Answered by
4
area of square=256cm^2
area of Triangle is half base ×height
so heigth=16cm
base=16cm
area=256/2=128cm^2
pls mark as brainliest answer.
suryahari248:
the previous one was area of unshaded region.
Answered by
10
HEY MATE!
YOUR ANSWER....
As it is a square, then all sides will be of 16 cm.
You need the area of shaded portions and both are triangles.
So, we need to find the area of both the triangles.
Triangle ABE:-
BE=4cm
AB=16 cm
![area = \frac{1}{2} \times base \times height area = \frac{1}{2} \times base \times height](https://tex.z-dn.net/?f=area+%3D+%5Cfrac%7B1%7D%7B2%7D+%5Ctimes+base+%5Ctimes+height)
![= \frac{1}{2} \times 4 \times 16 = \frac{1}{2} \times 4 \times 16](https://tex.z-dn.net/?f=+%3D+%5Cfrac%7B1%7D%7B2%7D+%5Ctimes+4+%5Ctimes+16)
![= 32 \: {cm}^{2} = 32 \: {cm}^{2}](https://tex.z-dn.net/?f=+%3D+32+%5C%3A+%7Bcm%7D%5E%7B2%7D+)
Triangle CDE:-
CE= 12 cm
CD= 16 cm
![area = \frac{1}{2} \times 12 \times 16 area = \frac{1}{2} \times 12 \times 16](https://tex.z-dn.net/?f=area+%3D+%5Cfrac%7B1%7D%7B2%7D+%5Ctimes+12+%5Ctimes+16)
![= 96 \: {cm}^{2} = 96 \: {cm}^{2}](https://tex.z-dn.net/?f=+%3D+96+%5C%3A+%7Bcm%7D%5E%7B2%7D+)
Area of shaded portion= 96+32 cm= 128 cm^2.
HOPE IT HELPS!
^_^
#happytohelp:)
YOUR ANSWER....
As it is a square, then all sides will be of 16 cm.
You need the area of shaded portions and both are triangles.
So, we need to find the area of both the triangles.
Triangle ABE:-
BE=4cm
AB=16 cm
Triangle CDE:-
CE= 12 cm
CD= 16 cm
Area of shaded portion= 96+32 cm= 128 cm^2.
HOPE IT HELPS!
^_^
#happytohelp:)
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