Math, asked by shalini683, 1 year ago

Find the area of the shaded region in the following figure.
In the figure,ABCD is a square.



Please explain

Please answer it correctly

I will mark you as brainlist

Please answer it very fast

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Answers

Answered by suryahari248
4

area of square=256cm^2

area of Triangle is half base ×height

so heigth=16cm

base=16cm

area=256/2=128cm^2

pls mark as brainliest answer.


suryahari248: the previous one was area of unshaded region.
suryahari248: hey u havnt rated yet i. Plz rate me as brainlist i need it fr my next rank.
shalini683: You have not explained
suryahari248: Cant u understand it dear
shalini683: You have not explained
suryahari248: the concept is simple buddy in squares all sides are equal. And frm ur diagram it cms to be 16cm.
suryahari248: and if u draw a line perpendicular to ad to point e that becomes the height of that triangle.
suryahari248: thats too 16cm as the distance b/w the sides is always equal in a square . And the base is ad which is 16cm and the formula fr area of triangle i hv araedy stated.
suryahari248: we get area of unshaded region and if u subtract that from area of square u get area of shaded region.
suryahari248: u got it buddy . I hope i made the concept clear .isnt it atlest now markme as brainliest.
Answered by TheAstrophile
10
HEY MATE!

YOUR ANSWER....

As it is a square, then all sides will be of 16 cm.

You need the area of shaded portions and both are triangles.

So, we need to find the area of both the triangles.

Triangle ABE:-
BE=4cm
AB=16 cm

area = \frac{1}{2} \times base \times height

 = \frac{1}{2} \times 4 \times 16

 = 32 \: {cm}^{2}

Triangle CDE:-
CE= 12 cm
CD= 16 cm

area = \frac{1}{2} \times 12 \times 16

 = 96 \: {cm}^{2}

Area of shaded portion= 96+32 cm= 128 cm^2.

HOPE IT HELPS!

^_^

#happytohelp:)

TheAstrophile: pls mark as brainliest if my answer is helpful 2 u
shalini683: Please follow me
suryahari248: u hv gone a long way stephanie
TheAstrophile: yeah but that's understandable
suryahari248: yeah.
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