find the area of the shaded region in the following figure
Attachments:
Answers
Answered by
8
Answer:
259.875 m²
Step-by-step explanation:
Area of bigger circle = pie × (radius)²
Radius = Diameter/2
= (22/7) × (21/2)²
= (22/7) × (21/2) × (21/2)
= (11 × 3 × 21) /2
= 693/2
Area of two semicircles = area of one circle ( as semi circles are identical)
= (22/7) × (21/4)²
= (22/7) × (21/4) × (21/4)
= (11 × 3 × 21) /8
= 693/8
Area of shaded region = 693/2 - 693/8
= (693/8)(4-1)
= (693/8)×3
= 259.875 m²
Tejash70:
thank you bro
Answered by
9
It is given that the diameter of the big circle is 21 m
So, its radius=(Diameter/2) m=21/2m
Now, area of the big circle=πr²
=22/7×(21/2)²
=22/7×441/4
=693/2 m²
So, we have the area of the big circle as 693/2 m²
In the above given figure, there are 2 semi-circles of equal diameter 10.5 m, and when we join these 2 semi-circles, we get a circle.
Its radius=(Diameter/2) m=10.5/2 m
So, area of that circle=πr²
=22/7×(10.5/2)²
=22/7×441/16
=693/8 m²
Now, area of the remaining/shaded portion=Area of the big circle-Area of the circle obtained by joining two semi-circles in the above give picture.
=(693/2-693/8) m²
=2079/8 m²
=259.875 m²
So, its radius=(Diameter/2) m=21/2m
Now, area of the big circle=πr²
=22/7×(21/2)²
=22/7×441/4
=693/2 m²
So, we have the area of the big circle as 693/2 m²
In the above given figure, there are 2 semi-circles of equal diameter 10.5 m, and when we join these 2 semi-circles, we get a circle.
Its radius=(Diameter/2) m=10.5/2 m
So, area of that circle=πr²
=22/7×(10.5/2)²
=22/7×441/16
=693/8 m²
Now, area of the remaining/shaded portion=Area of the big circle-Area of the circle obtained by joining two semi-circles in the above give picture.
=(693/2-693/8) m²
=2079/8 m²
=259.875 m²
Similar questions