Question

Find the area of the shaded region in the given figure
class 10 ch areas related to circles
maths​

Answer 1

Answer:

L = 26 m

B = 12 m

d = 12-(4+4) = 12-8 = 4 m

r = d/2 = 4/2 = 2 m

b = 4 m

l = L - ( 3 + 3 + r + r )

= 26-(6+2+2)

= 26 - 10

= 16 m

area of shaded region = area of rectangle - 2 area's of semi-circle - area of Internal rectangle

$= l \times b - 2 \times \frac{\pi {r}^{2} }{ 2} - l \times b \\ \\ = 26 \times 12 - \pi {r}^{2} - 16 \times 4 \\ \\ = 312 - \frac{22}{7} \times {2}^{2} - 64 \\ \\ = 248 - \frac{22}{7} \times 4 \\ \\ = 248 - \frac{88}{7} \\ \\ = 248 - 12.57 \\ \\ = 235.43 \: {cm}^{2}$

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Answer 2

Answer:

Answer is 235.43 cm

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