Question

find the area of the shaded region in the given figure if AC=24 cm BC=10 cm and all the centre of the circle

Answer 1

Answer:

Step-by-step explanation:

area of shaded region =area of circle-area of triangle

                                       radius of the circle =ab/2

                                     AB=26[by pythagores theorem]

• ∴radius=13cm
• area of circle-area of triangle=

                           pi r2 -1/2bh=22/7*13*13-1/2*24*10

                                               =286/7*13-120

                                               =3718/7-120

                                                 =531.15-120

                                                 =411.15

Answer 2

Answer:

Area of shaded region is 410.66 square cm

Step-by-step explanation:

In the give figure, AC=24 cm BC=10 cm

we have to find the area of shaded region.

Area of triangle ABC can be calculated as

= $\frac{1}{2}\times base\times height =\frac{1}{2}\times BC\times AC$

=  $\frac{1}{2}\times 10\times 24=120cm^2$

By Pythagoras theorem,

$AB^{2}=AC^{2}+BC^{2}$

⇒ $AB^{2}=24^{2}+10^{2}$

⇒ $AB^{2}=676$ ⇒ AB=26 cm

Diameter of circle,d=AB=26 cm

∴ Radius= 13 cm

⇒  $Area of circle = \pi \times r^2$

                          = $3.14\times 13 \times 13=530.66 cm^2$

Area of shaded region = Area of circle-ar(ΔABC)

                                      = $530.66-120=410.66cm^2$

Area of shaded region is 410.66 square cm