Find the area of the shaded region in the given figure. If BC=BD=8cm, AC=AD=15cm and O is the centre of the line ( π = 3.14)
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Step-by-step explanation:
there will be right angles at C and D points as shown in the figure
then AB will be the hypothesis of the right angle triangle ACB
then from pythogorous theroem,
(AB)^2=(AC)^2+(CB)^2
(AB)^2= (15)^2+(8)^2 = 225+64 =289
(AB)=√(289)
AB=17 cm
AB is the diameter of the circle
then radius of the circle is AB/2=17/2
area of shaded region(A.S.R)=area of circle-2(area
of triangle)
A.S.R=πr^2-2(1/2)(base)(height)
A.S.R=(3.14)(17/2)^2-(8)(15)
A.S.R=(3.14)(289/4)-(120)
A.S.R=226.865-120
A.S.R=106.865 cm^2
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