Question

find the area of the shaded region in the given figure q9

Answer 1

Area of shaded part = Area of semicircle - Area of traingle

Now,
The given triangle will be a right angled triangle since angle PEQ will be 90° by Inscribed angle theorem since PQ is diameter.

So,
SE = ER = 10√2/2 = 5√2
Now
PE = EQ = √ (5√2)^2+(5√2)^2 = √50+50 = 10 cm

Now
Area of shaded region = πr^2 / 2 - 1/2* base*height
= π*(5√2)^2/2 - 1/2*10*10
= π*25-50 = 25(π-2) = 25*1.142 cm^2

Now, hope you can calculate this further.

Hope this helps you !