Question

FIND THE AREA OF THE SHADED REGION in the given figure , where a circular arc of radius 7cm has been drawn with vertex o of an equilateral triangle oab of side 12 cm , as centre

Answer 1

Answer:

190.57  sq.cm

Step-by-step explanation:

Side of equilateral triangle = 12 cm

Area of equilateral triangle =$\frac{\sqrt{3}}{4}a^2$

                                             =$\frac{\sqrt{3}}{4}(12)^2$

                                             =$62.35$

All angles of equilateral triangle is of 60°

So, ∠AOB = 60°

Radius of circle = 7 cm

Area of sector of circle included in triangle =$\frac{\theta}{360}\pi r^2$

                                                                         =$\frac{60}{360} \times 3.14 \times 7^2$

                                                                         =$25.64$

Area of circle = $\pi r^2$

                      = $3.14 \times 7^2$    

                      = $153.86$    

So, Area of shaded region = Area of triangle +Area of circle - Area of sector

                                            =62.35+153.86-25.64

                                            =190.57  sq.cm

Hence the area of the shaded region is 190.57  sq.cm                                                                        

Answer 2

Answer:

Here is your answer

Step-by-step explanation:

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