Question

find the area of the shaded region


plz answer I will mark you as branliest answer​

Answer 1

Answer:

H squarr = P square + B square

h square = 12square + 16square

h square= 144 + 256

h square = 400

h= 20

so, h= 20

area of this traingle= 1/2*b*h

=1/2*16*12

=96

area of big triangle= 1/2* b*h

= 1/2*48*20

=480

shaded part area = 480-96

=384

hope so this answer would be correct

thanks

Answer 2

First, lets find the length of the remaining side in that unshaded right angled Triangle.

By Pythagorus Theorum-

${H}^{2} = {P}^{2} + {B}^{2} \\ {H}^{2} = {16cm}^{2} + {12cm}^{2} \\ {H}^{2} = 256{cm}^2 + 144{cm}^2 \\ {H}^{2} = 400{cm}^2 \\ {H} = \sqrt{400{cm}^2} \\ H = 20cm$

Area of Right-Angled Triangle

$= \frac{1}{2} \times Base \times Height \\ = \frac{1}{2} \times 16cm \times 12cm \\ = 96 {cm}^{2}$

Now, we find area of Large Traingle

As, there is no altitude we can use Herons Formula

$\sqrt{s(s - a)(s - b)(s - c)} \\ Semi \: Perimeter \: = \frac{a + b + c}{2} \\ = \frac{48 + 52 + 20}{2} \\ = \frac{120}{2} = 60 \\ \sqrt{60(60 - 48)(60 - 52)(60 - 20)} \\ = \sqrt{60 \times 12 \times 8 \times 40} \\ = 480 {cm}^{2}$

Now to Calculate Area of Shaded Region,

We Subtract the Area of Small Triangle from the Large Traingle.

$480 {cm}^{2} - 96 {cm}^{2} \\ = 384 {cm}^{2}$

Be Brainly.