find the area of the shaded region ppzzz
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AB=BC=AC(given)
BC=10cm(given)
therefore,
AB=AC=10cm
thus,area of equilateral triangle ABC=(√3/4)×side^2=(√3/4)×10^2=43.3cm^2
are of triangle BDC=1/2×BASE×HEIGHT=1/2×8×10=40cm^2
therefore shaded area=Area of triangle ABC-Area of triangle BDC=43.3-40=3.3cm^2
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