find the area of the shaded region shown in figure 6
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Answer:
32m²
Step-by-step explanation:
length =4m
breadth = 5 +5 =10m
total area of the rectangle = l × b = 4 x 10 = 40m²....i
now, for area of the unshaded region.
it is comprise of two triangles with equal height.
let the first triangle be T1 and the other be T2.
Height of T1 = 4 x 1/2 = 2m
Base =3m
area of a triangle = 1/2 × base × height
=> area of T1 = 1/2 ×3m×2m
=> area of T1= 3m²
Height of T2 = 2m
Base = 5m
=> area of T2 = 1/2 ×5m×2m
=> area of T2 = 5m²
therefore, total area of the unshaded region = area of T1 +T2
=> total area of unshaded region = 3m² + 5m² = 8m²....ii
thus, area of shaded region = total area of the rectangle -
total area of the unshaded region
from i and ii,
area of shaded region = 40m² - 8m² = 32m²
mark this as brainlest, please
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