Question

Find the area of the shaded regions​

Answer 1

Answer:

$area \: of \: the \: shaded \: region = area \: of \: trapezium - area \: of \: triangle \\ area \: of \: trapzium = \frac{1}{2} \times sum \: of \: parallel \: sides \times height \\ = \frac{1}{2} \times (7.4 + 9.6) \times 12 \\ = \frac{1}{ \cancel2} \times 17 \times \cancel{12} \\ = 17 \times 6 = 102 \: {cm}^{2} \\ area \: of \: triangle = \frac{1}{2} \times base \times height \\ = \frac{1}{2} \times 9.6 \times 12 \\ = \frac{1}{ \cancel2} \times 9.6 \times \cancel{12} \\ = 9.6 \times 6 = 57.6 \: {cm}^{2} \\ area \: of \: the \: shaded \: region = area \: of \: trapezium - area \: of \: triangle \\ = 102 - 57.6 = 44.4 \: {cm}^{2} \\ \purple{\boxed{ \red{area \: of \: the \: shaded \: region =44.4 \: {cm}^{2} }}} \\ \green{ \frak{which \: is \: the \: required \: answer.}}$

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