Question

Find the area of the square formed by (0,-1), (2,1),(0,3) and (-2,1) as vertices

Answer 1

Usning Distance Formula

Length of 1 side of square

$= \sqrt{ ({2 - 0})^{2} + ( { - 1 - 1})^{2} } \\ \\ = \sqrt{4 + 4} \\ \\ = \sqrt{8}$

Now , Area of square

= side × side

= $\sqrt{8} × \sqrt{8}$

= 8 sq. unit

Answer 2

Answer:

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