Question

find the area of the square having the length of side 8 cm

Answer 1

Given:-

•Length of side is 8cm.

To Find:-

•Find the area of square.

Solution:-

we have,

• side = 8cm

Using Formula:

$\: \: \sf \: area \:of \: square = {(side)}^{2}$

Now substitute the values，

$\: \: \sf \: area \: of \: square = {(8)}^{2} \\ \\ \: \: \sf \: area \: of \: square = 64 {cm}^{2}$

Hence,area of square is 64cn^2.

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Extra Info...

$\: \: \sf \: perimeter \: of \: square = 4 \times side \\ \\ \: \: \sf \: perimeter \: of \: rectangle = 2(length + breadth) \\ \\ \: \: \sf \: area \: of \: rectangle = length \times breadth \\ \\ \: \: \sf \: length\: of \: rectangle = \frac{area}{breadth} \\ \\ \: \: \sf \: breadth \: of \: rectangle = \frac{area}{length}$

Answer 2

Answer

Hence, Area of square will be 64 Sq. cm

Step-by-step explanation:

In context to question asked,

We have to determine the area of the square.

As per question,

We have,

Side of square = 8 cm

As we know that,

Square is a quadrilateral whose all sides are equal.

The area of square can be determined by using the formula $Area = Side^2$

So, for determining the area of square we will put the value of side of square in above formula,

Thus we will get the area of square as,

$Area = 8^2\\=>Area = 8\times 8\\=>Area = 64\:cm^2$