Find the area of the square insribed in a circle of radius 8 cm
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Answered by
0
Answer:
Let ABCD be the square inscribed by the circle.
∴OA=OB=OC=OD
ABC is a right angled triangle, as OA=8,OB=8
AB=8+8=16
According to Pythagoras theorem,
Square of hypotenuse = Sum of squares of other two sides.
AC
2
=AB
2
+BC
2
As ABCD is a square all the sides are equal, AB=BC
AC
2
=2AB
2
16
2
=2AB
2
∴AB=8
2
therefore side of the square =8
2
Area of square =(8
2
)
2
=128cm
2
Answered by
2
Answer:
128cm²
Step-by-step explanation:
answer will be 128 cm²
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