Question

find the area of the square that can be inscribed in a circle of radius 8 cm.

Answer 1

Diagonal of square = Diameter of circle

=> side *root2 = 8* 2

=> Side * Root 2 = 16

=> Side of square = ( 16/root2) cm

Area = Side^2

= (16/root2) ^2

= 256 / 2

= 128 cm^2

Answer 2

Radius of circle=8

Then, diameter =16cm

As the diameter of circle is equal =diagonal of square

16= diagonal of square,

Let the side of square =x

By Pythagoras theorem,

16²=x²+x²

256=2x²

128=x²

Then area of square =side²=x²

128=x²

Area of square =128cm²

I hope this will help you