find the area of the square that can be inscribed in a circle of radius 8 cm
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as the square in inscribed in circle, then
diameter of circle = diagonal of square
2*8= diagonal of square
16=diagonal of square
let the side of square is x
then by pythagoras theorem,
x^2 + x^2 = 16^2
2x^2 = 256
x^2 =256/2
x^2 =128
area of square is side^2, as the x is side then area is x^2
x^2 = 128
then area of square is 128cm^2
diameter of circle = diagonal of square
2*8= diagonal of square
16=diagonal of square
let the side of square is x
then by pythagoras theorem,
x^2 + x^2 = 16^2
2x^2 = 256
x^2 =256/2
x^2 =128
area of square is side^2, as the x is side then area is x^2
x^2 = 128
then area of square is 128cm^2
Anonymous:
let it go
it's ok
bro i am asking genuinely
you can observe it
make a diagram
then see
in that
inscribe karenge to diagonal points to touch hi nahi honge
i mean the corners
yeah @abhi is right, diameter of the circle is the diagonal of the square
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area of square is 128cm^2
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