Find the area of the square that can be inscribed in a circle of radius 8 cm.
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Answered by
1
side of square = √2×r
area of square = (√2r)^2
= (√2×8)^2
= 128 cm^2
= 0.128 m^2
area of square = (√2r)^2
= (√2×8)^2
= 128 cm^2
= 0.128 m^2
Answered by
8
The radius of the circle is 8 cm so the length of half of the diameter is 8cm. Then the diagonal of the square is 16 cm.let the side of the square be x. By Pythagorean theorem
x^2+x^2=16^2
2*x^2=256
x^2=256÷2
x^2=128
x=√128
side is √128
area is √128*√128=
128cm^2
x^2+x^2=16^2
2*x^2=256
x^2=256÷2
x^2=128
x=√128
side is √128
area is √128*√128=
128cm^2
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