Question

find the area of the square that can be inscribed in a circle of radius 8 cm

Answer 1

Given,  Radius = r=8cm  ∵ The diagonals of square subtend right angle at circumference.  ∴The diagonals of square are diameters of circle.  BD = 2*8 = 16cm  Let the sides of square be 'x' cm  in the right angle triangle BCD,  BC² +CD² = BD²  x² + x² = 16²  2x² = 256  x² = 128  Thus the area of square is x² = 128cm²    

Answer 2

The diameter of the circle is 16.
The diameter will be the diagonal of the largest square drawn in it.
So the area will be= 1/2×(16)^2=128sq.cm.