find the area of the square whose diagonal is 5.2cm
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We know that the measure of each angle of square is 90°.
By Pythagoras Theorem,
side^2 + side^2 = diagonal^2
2 side^2 = ( 5.2 )^2
2 side^2 = 27.04
side^2 = 27. 0 4 / 2
side^2 = 13.52 cm^2 ....( i )
we know that the area of square is side^2, from ( i )
Area of the square = side^2
= 13.52 cm^2
Therefore area of the square is 13.52 cm^2
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