find the area of the square whose diagonal is12cm
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0
Answer:
(12)*2=a*2+a*2
144=2a*2
a*2=72
Area=72
Answered by
2
Answer:
Diagonal = 12 cm
Let side be = x
In the given figure:
By Pythagoras Theorem in Triangle ADC:
AC^2 = AD^2 + CD^2
=> 12^2 = x^2 + x^2
=> 144 = 2x^2
=> x^2 = 72
We know that area of a square = square of its side = x^2
We got x^2 = 72
Thus, area = 72 sq cm
Hope it Helps!!
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