Question

Find the area of the square whose perimeter is equal to a rectangle whose area is 39cm² and length is 13cm.​

Answer 1

Step-by-step explanation:

perimeter of rectangle = 2(l+b)

rectangle area =l×b

area of rectangle = 39

length = 13

so

$\frac{area}{length} = breadth \\ \frac{39}{13} = 3 \\ breadth \: \: = 3cm \\ now \: perimeter = 2(l + b) \\ 2(39 + 13) \\ 2(52) = 104cm \\ square \: perimeter = rectangle \: perimeter \\ so \: 104 = 4a \\ a = \frac{104}{4} = 26 \\ a = 26cm \\ a = side \: of \: square \\ area \: of \: square = a^{2} \\ a = 26 \\ 26^{2} = 676cm^{2} \\ area \: of \: square \: = 676cm^{2}$

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