find the area of the squre whose sde formed the diagonal of the square whose side is 6cm
Answers
side of square = 6cm
Diagonal of square =√2×side
=6√2 cm
Diagonal of square = Side of square formed
Side of square =6√2 cm
Area of square formed = (side)^2
= (6√2)^2
= 36×2
=72cm^2
Given: The side of a square whose diagonal is the side of another square is 6cm.
To find: The area of the square whose side is the diagonal of the given square.
Solution:
Let's start by finding the length of the side of the given square.
The diagonal of a square with side length 's' can be found using the Pythagorean theorem as follows:
diagonal^2 = s^2 + s^2
diagonal^2 = 2s^2
s^2 = diagonal^2 / 2
s = diagonal / sqrt(2)
In our case, the side of the given square is 6cm, so its diagonal is:
diagonal = 6 * sqrt(2)
Now, find the side of the second square as follows:
s = diagonal / sqrt(2)
s = (6 * sqrt(2)) / sqrt(2)
s = 6 cm
The area of a square is given by the formula A = s^2, so the area of the second square is:
A = 6^2 = 36 sq cm
Therefore, the area of the square whose side is the diagonal of the given square is 36 sq cm.
To learn more about square root from the given link.
https://brainly.in/question/54182389
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