Question

find the area of the thin sheeting required for making an open cistern,5m long,3m wide,4m deep

Answer 1

hGiven measurements,
length=5m
width=3m
deep=4m

T.S.Aof rectangle=2(lb+BH+HL)
=>2(5*3+3*4+4*5)
=>2(15+12+20)
=>2(47)
=>94m²

Hence, area of thin sheet required= 94m².

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Answer 2

Given,

Length =l= 5 m 

Breadth =b= 3 m 

Height = depth =h= 4 m

TSA = 2 ( lb + bh + hl )

but by condition without lid 

here TSA = 2 ( lb + bh + hl ) - lb 

= 2 ( 15 + 12 + 20 ) - 15 

= 2 ( 47 ) - 15 = 94 - 15 = 79 sq.m