Question

Find the area of the thin sheeting required for making an open cistern(i.e,without a lid),5m long 3m wide,4m deep​

Answer 1

$l$ = 5 m

$b$ = 3 m

height = depth = 4 m

Total Surface Area = 2 ( $lb$ + $bh$ + $hl$ )

By condition without lid

Here Total Surface Area = 2 ( $lb$ + $bh$ + $hl$ )  -  $lb$

= 2 ( 15 + 12 + 20 ) - 15

= 2 ( 47 ) - 15

= 94 - 15

= 79 sq.m

Amannnscharlie

Answer 2

Answer:

Area of sheet required= lb+ 2lh+2bh

= 5*3 + 2*5*4 + 2*3*4

= 15 + 40 + 24

= 79m^2