Question

find the area of the traingle having vertices (-3,1),(-2,-2)and(3,2)​

Answer 1

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Answer 2

${\bold{\sf{(x_{1},y_{1}) = (-3,1)}}}$

${\bold{\sf{(x_{2},y_{2}) = (-2,-2)}}}$

${\bold{\sf{(x_{3},y_{3}) = (3,2)}}}$

${\bold{∆=\dfrac{1}{2}|x_{1}(y_{2}-y_{3})+x_{2}(y_{3}-y_{1})+x_{3}(y_{1}-y_{2})|}}$

${\bold{∆=\dfrac{1}{2}|-3(-2-2)-2(2-1)+3(1+2)|}}$

${\bold{∆=\dfrac{1}{2}|-3(-4)-2(1)+3(3)|}}$

${\bold{∆=\dfrac{1}{2}|12-2+9|}}$

${\bold{∆=\dfrac{1}{2}×19}}$

${\bold{∆=9.5}}$