Question

Find the area of the trapezium answer for this please

Answer 1

The area of a trapezoid is equal to the sum of the areas of the two triangles and the area of the rectangle.

We know that

area of trapezoid = area of triangle 1 + area of rectangle + area of triangle 2.

That means,

$\sf\longmapsto A = ( \frac{ ah}{2} ) + b1h + ( \frac{ch}{2} ) \\ \\ \\ \sf\longmapsto \: A = \frac{(ah + 2b_1h + ch)}{2}$

Simplifying the equation, rearranging the terms, and factoring result to:

$\sf\longmapsto A = \frac{h}{2} \big\lgroup b_1 + (a + b_1 + c) \big\rgroup….(i)$

If we assume the longer base of the trapezoid be $\sf \: b_2$, then

$\sf\longmapsto b_2 = a + b_1 + c \: \: \: …..(ii)$

Substituting (ii) in equation (i),

$\sf\longmapsto A = \frac{h}{2} (b_1 + b_2)$

Therefore, the area of a trapezoid with bases $\sf b_1, b_2$ and altitude h is;

$\sf \longmapsto \: A = \frac{h}{2} (b_1+b_2)$

Answer 2

Answer:

what is marginalisation ?