Question

find the area of the trapezium if the distance between its parallel sides is 26 cm and one of the parallel sides is 84 cm long. the other parallel side is half of the perpendicular distance between the parallel sides .​

Answer 1

Answer :

1261cm²

Explanation :

In a trapezium,

• One of the parallel side is 84cm long and another parallel side is half of the perpendicular distance.
• The distance between the parallel side is 26cm.

Here, the perpendicular side refers to the distance between parallel sides.

∴ Another parallel side : ½ × 26

= 13cm.

Now,

Area of a trapezium : ½(a + b)h

Where,

• (a + b) is the sum of parallel sides i.e., (84 + 13)
• 'h' is the distance between the parallel sides i.e., 26cm

So,

→ ½(84 + 13)26

→ ½ • 97 • 26

→ 97 • 13

→ 1261

∴ The area of the trapezium is 1261cm²

Answer 2

Given:-

• In a trapezium one of it's parallel side is 84 cm long and other side half of it's height.
• Length of it's height is 26 cm.

To Find:-

• Area of trapezium?

Solution:-

Formula to find area of trapezium:-

$\dag{ \boxed{ \underline{ \pink{ \frac{1}{2} \times (a + b) \times h }}}}$

Where,

• a and b are parallel sides of trapezium.
• h is height of trapezium.

According to the question:-

• 1st Parallel side = 84 cm
• 2nd Parallel side = ½ × 26 = 13 cm
• Height = 26 cm

So,

$☞ \frac{1}{2} \times (84 + 13) \times 26 \\ \\ ☞\frac{1}{2} \times 97 \times 26 \\ \\ ☞ \frac{1}{2} \times 2522 \\ \\ ☞ \dag{ \boxed{ \underline{ \blue{ {1261}^{2} }}}}$

Therefore, the area of trapezium is 1,261 cm².