Question

find the area of the trapezium if the parallel sides are measuring height 4cm a=17cm b=14cm​

Answer 1

Answer:

A=a+b/2h

17+14/2×4=62cm^2

Answer 2

ANSWER✔

$\large\underline\bold{GIVEN,}$

$\sf\dashrightarrow height(h)=4cm$

$\sf\dashrightarrow parallel side_1(a)=17cm$

$\sf\dashrightarrow parallel side_2(b)=14cm$

$\large\underline\bold{TO\:FIND,}$

$\bf\dashrightarrow\purple{AREA\:OF\:TRAPEZIUM.}$

✯FOMULA IN USE,

$\large{\boxed{\bf{ \dfrac{1}{2} \times (sum\:of\:parallel\:sides[a+b]) \times height.}}}$

$\large\underline\bold{SOLUTION,}$

$\sf\therefore \dfrac{1}{2} \times (a+b) \times height$

$\sf\implies \dfrac{(14+17)}{2} \times (4)$

$\sf\implies \dfrac{31}{2} \times 4$

$\sf\implies \dfrac{31}{\cancel{2}} \times \cancel{4}$

$\sf\implies 31 \times 4$

$\sf\implies 62cm^2$

$\large{\boxed{\bf{ \star\:\: 62cm^2\:\: \star}}}$

$\large\underline\bold{AREA\:OF\:TRAPEZIUM\:IS\:62cm^2}$

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