Question

find the area of the trapezium if the parallel sides are of 1.5m and 1.2mand perpendicular distance between them is 0.7 ​

Answer 1

$\huge\mathbb{SOLUTION:-}$

• We have to find the Area of trapezium

$\boxed{\sf{Area\:of\: trapezium=\frac{1}{2}\times (sum\:of\: parallel\:sides)\times height}}$

• Parallel sides = 1.5m and 1.2 m

• Height =0.7m

Now

$\bf\underline {\underline{\red{According\:To\: Question:-}}}$

$\sf\implies Area=\frac{1}{2}\times (1.5+1.2)\times 0.7\\ \\ \sf\implies Area=\frac{1}{2}\times 2.7\times 0.7\\ \\ \sf\implies Area=\cancel{\frac{1.89}{2}}=0.945\\ \\ \sf\implies Area=0.945m{}^{2}$

$\boxed{\sf{\purple{Area\:of\: trapezium=0.925m{}^{2}}}}$

Answer 2

Answer:

${\boxed{\bold\green{Area\:of\:trapezium=0.945\:{m}^{2}}}}$

Given that,

• Parallel sides = 1.5 m and 1.2 m
• Perpendicular distance = 0.7 m
• $\bold\green{Area\:of\:trapezium=\:?}$

Formula used:-

${\boxed{\bold{Area\:of\:trapezium=\frac{1}{2}\times (Sum\:of\:parallel\:sides)\times Distance}}}$

$\rightarrow\tt Area =\frac{1}{2}\times (1.5+1.2)\times 0.7 \\ \rightarrow\tt Area = \frac{1}{2}\times 2.7 \times 0.7 \\ \rightarrow\tt Area = 0.945 \:{m}^{2}$

$\therefore\bold{\underline{Area\:of\:trapezium=0.945\:{m}^{2}}}$